Day 2: Conditional Statements: Switch

Objective

In this challenge, we learn about switch statements. Check out the attached tutorial for more details.

Task

Complete the getLetter(s) function in the editor. It has one parameter: a string, s, consisting of lowercase English alphabetic letters (i.e., a through z). It must return A, B, C, or D depending on the following criteria:

• If the first character in string s is in the set {a, e, i, o, u}, then return A.
• If the first character in string s is in the set {b, c, d, f, g}, then return B.
• If the first character in string s is in the set {h, j, k, l, m}, then return C.
• If the first character in string s is in the set {n, p ,q,r, s, t, v, w, x, y, z}, then return D.
  Hint: You can get the letter at some index i in s using the syntax s[i] or s.charAt(i).

Input Format

Stub code in the editor reads a single string denoting s from stdin.

Constraints

• 1 <= |s| <= 100, where |s| is the length of s.
• String s contains lowercase English alphabetic letters (i.e., a through z) only.

Output Format

Return either A, B, C, or D according to the criteria given above.

Sample Input 0

1

adfgt

##Sample Output 0

1

AA

Explanation

The first character of string s = adfgt is a. Because the given criteria stipulate that we print A any time the first character is in {a, e, i, o, u}, we return A as our answer.

Solution

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function getLetter(s) {
  let letter;
  // Write your code here
  switch (s[0]) {
    case 'a' || 'e' || 'o' || 'i' || 'u':
      letter = 'A';
      break;

    case 'b' || 'c' || 'd' || 'f' || 'g':
      letter = 'B';
      break;

    case 'h' || 'j' || 'k' || 'l' || 'm':
      letter = 'C';
      break;

    case 'z' ||
      'n' ||
      'p' ||
      'q' ||
      'r' ||
      's' ||
      't' ||
      'v' ||
      'w' ||
      'x' ||
      'y':
      letter = 'D';
  }

  return letter;
}