Library Fine

Library Fine

Your local library needs your help! Given the expected and actual return dates for a library book, create a program that calculates the fine (if any). The fee structure is as follows:

  1. If the book is returned on or before the expected return date, no fine will be charged (i.e.: fine = 0).
  2. If the book is returned after the expected return day but still within the same calendar month and year as the expected return date, fine = 15 Hackos X (the number of days late).
  3. If the book is returned after the expected return month but still within the same calendar year as the expected return date, the fine = 500 Hackos X (the number of days late).
  4. If the book is returned after the calendar year in which it was expected, there is a fixed fine of 10,000 Hackos.

Charges are based only on the least precise measure of lateness. For example, whether a book is due January 1, 2017 or December 31, 2017, if it is returned January 1, 2018, that is a year late and the fine would be .

Function Description

Complete the libraryFine function in the editor below. It must return an integer representing the fine due.

libraryFine has the following parameter(s):

  • d1, m1, y1: returned date day, month and year
  • d2, m2, y2: due date day, month and year

Input Format

The first line contains 3 space-separated integers, d1,m1,y1, denoting the respective day, month, and year on which the book was returned.

The second line contains 3 space-separated integers, d2,m2,y2, denoting the respective day, month, and year on which the book was due to be returned.

Constraints

  • 1 <= d1,d2 <= 31
  • 1 <= m1,m2 <= 12
  • 1 <= y1,y2 <= 3000

Output Format

Print a single integer denoting the library fine for the book received as input.

Sample Input

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2
9 6 2015
6 6 2015

Sample Output

1
45

Explanation

Given the following dates:

Returned: d1 = 9, m1 = 6, y1 = 2015

Due: d2 = 6, m2 = 6, y2 = 2015

Because , we know it is less than a year late.

Because , we know it’s less than a month late.

Because , we know that it was returned late (but still within the same month and year).

Per the library’s fee structure, we know that our fine will be 15 Hackos X (# days late). We then print the result of 15 X (d1 - d2) = 15 X (9 - 6) = 45 as our output.


Solution

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// Complete the libraryFine function below.
function libraryFine(d1, m1, y1, d2, m2, y2) {
return (
y1 > y2 ? 10000 : (
y2 > y1 ? 0 : (
m1 > m2 ? 500 * ((m1 - m2) + ((y1 - y2) * 12)) : (
m2 > m1 ? 0 : (
d1 > d2 ? 15 * (d1 - d2) : 0
)
)
)
)
);
}
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